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8x^2-120x-432=0
a = 8; b = -120; c = -432;
Δ = b2-4ac
Δ = -1202-4·8·(-432)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28224}=168$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-168}{2*8}=\frac{-48}{16} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+168}{2*8}=\frac{288}{16} =18 $
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